Question

If A, B and C are three points on a circle, where BC is the diameter and AC = AB = 5√2 cm. Find the radius of the circle.

• A. 6 cm
• B. 5 cm
• C. 5/√2 cm
• D. 4 cm

Answer 1

Answer:

B. 5 cm

As we know,

⇒ ∠BAC is 90 and BC is diameter,

⇒ AB = AC = 5√2

In ΔBAC

⇒ BC² = AB² + AC²

⇒ BC² = (5√2)² + (5√2)²

⇒ BC² = 50 + 50

⇒ BC = √100

⇒ BC = 10 cm

Radius of the circle = $\frac{10}{2}$ = 5 cm.