If at same rate of interest, in 2 years, the simple interest is ₹40 and compound interest is ₹44, then what is the principal (in ₹)?A100B95C104D93Answer: A. 100 Read Explanation: Given:Simple Interest (SI) for 2 years = ₹40Compound Interest (CI) for 2 years = ₹44For 2 years,CI−SI=P⋅r21002\text{CI} - \text{SI} = \frac{P \cdot r^2}{100^2}CI−SI=1002P⋅r2 Find the difference44 - 40 = 4⇒P⋅r210000=4\Rightarrow \frac{P \cdot r^2}{10000} = 4⇒10000P⋅r2=4P⋅r2=40000(1)P \cdot r^2 = 40000 \quad \text{(1)}P⋅r2=40000(1)Use SI formulaSI=P⋅r⋅t100\text{SI} = \frac{P \cdot r \cdot t}{100}SI=100P⋅r⋅t40=P⋅r⋅210040 = \frac{P \cdot r \cdot 2}{100}40=100P⋅r⋅2P⋅r=2000(2)P \cdot r = 2000 \quad \text{(2)}P⋅r=2000(2)Divide (1) by (2)Pr2Pr=400002000\frac{P r^2}{P r} = \frac{40000}{2000}PrPr2=200040000r = 20%Find (P)P⋅r=2000P \cdot r = 2000P⋅r=2000P⋅20=2000P \cdot 20 = 2000P⋅20=2000P = 100$ Read more in App