Challenger Logo

Challenger App

Get it on Google PlayGet it on App Store
App Logo

No.1 PSC Learning App

★
★
★
★
★
1M+ Downloads
Get App
If cos 9a = sin ɑ and 9ɑ < 90° , then the value of tan 5ɑ is

A1/√3

B√3

C1

D0

Answer:

C. 1

Read Explanation:

cos (90-x) = sin x cos 9ɑ = sin ɑ cos 9ɑ = cos(90-ɑ) 9ɑ+2 = 90 10ɑ = 90 ɑ = 9 tan 5ɑ = tan (5 x 9) = tan 45 =1

Related Questions:

If sec 44 cosec (3A-50°), where 44 and 34 are acute angles, find the value of A + 75.

The value of cosec230∘sin⁡245∘+sec⁡260∘tan60∘cosec245∘−sec⁡260∘tan45∘\frac{{\rm cose{c^2}30^\circ {{\rm \sin }^2}45^\circ + {{\rm \sec }^2}60^\circ }}{{\rm tan60^\circ \rm cose{c^2}45^\circ - {{\rm \sec }^2}60^\circ \rm tan45^\circ }}  is:

If sec3x = cosec(3x - 45°), where 3x is an acute angle, then x is equal to:

Find the Value ofcos⁡30∘−sin⁡30∘sin⁡60∘+cos⁡60∘\frac{\cos 30^\circ - \sin 30^\circ}{\sin 60^\circ + \cos 60^\circ}

image.png