Question

If $\frac{x}{y}=\frac{3}{2}$ ,then find $\frac{x^2+y^2}{x^2-y^2}$

• A. $$\frac{13}{5}$$
• B. $$\frac{11}{5}$$
• C. $$\frac{7}{5}$$
• D. $$\frac{9}{5}$$

Answer 1

Answer:

$$\frac{13}{5}$$

Given, $\frac{x}{y}=\frac{3}{2}$

Hence, $\frac{x^2+y^2}{x^2-y^2}=\frac{3^2+2^2}{3^2-2^2}$

$=\frac{9+4}{9-4}=\frac{13}{5}$