If points (a,0),(0,b)and(1,1) are collinear, then (a−1+b−1)(a^{-1} + b^{-1})(a−1+b−1) will be equal to : A-1B-2C1D√2Answer: C. 1 Read Explanation: 1/2 [x₁(y₂-y₃) + x₂(y₃-y₁)+x₃(y₁-y₂)]=0|a(b-1)+0(1-0)+1(0-b)|=0 ab-a-b=0 ab=a+b 1=a+bab1=\frac{a+b}{ab}1=aba+b1a+1b=1\frac{ 1}{a}+\frac{ 1}{b}=1a1+b1=1a−1+b−1=1a^{-1}+b^{-1}=1a−1+b−1=1 Read more in App
