Question

If the average of m numbers is n² and that of n numbers is m², then average of (m + n) numbers is

• A. m+n
• B. mn
• C. m-n
• D. mn²+m²n

Answer 1

Answer:

B. mn

Total number of ‘m’ numbers = m × n² Total number of ‘n’ numbers = n × m² Average of (m + n) numbers=mn²+m²n/m+n =mn(n+m)/m+n =mn