Question

If the number 476**0 is divisible by both 3 and 11, then in the hundredth and tenth places, the non-zero digits are, respectively:

• A. 2 and 3
• B. 3 and 2
• C. 5 and 8
• D. 8 and 5

Answer 1

Answer:

D. 8 and 5

Divisibility rule of 3 = If the sum of digits of a number is a multiple of 3, the number will be completely divisible by 3 Divisibility rule of 11 = If the difference of the sum of alternative digits of a number is divisible by 11 or it is 0, then that number is completely divisible by 11. On considering option 8 and 5 ,The number is 476850 Sum of the digits = 4 + 7 + 6 + 8 + 5 + 0 = 30,which is divisible by 3 Sum of digits at odd places = 4 + 6 + 5 = 15 Sum of digits at even places = 7 + 8 + 0 = 15 Difference = 15 -15 = 0 this is divisible by 11 as well