Challenger App

No.1 PSC Learning App

1M+ Downloads
ഒരു ത്രികോണത്തിന്റെ വശങ്ങൾ 3 cm, 4 cm, 5 cm ആയാൽ ആ ത്രികോണത്തിന്റെ വിസ്തീർണം കാണുക :

A9 cm²

B6 cm²

C10 cm²

D15 cm²

Answer:

B. 6 cm²

Read Explanation:

area=√(s(s-a)(s-b)(s-c)) s= a+b+c/2 = 3+4+5/2= 6 area = √(6 ( 6-3)(6-4)(6-5)) = √(6 x 3 x 2 x 1 )= √36 = 6cm²


Related Questions:

The lengths of the two diagonals of a rhombus are 20 cm and 23 cm. What is the area (in cm?) of the rhombus?
A circular fountain with a radius of 7 m is encircled by a grass bed that is 3.5 m wide. Determine the ratio of the area of the grass bed to the area of the fountain.
if sin(90° - x) = cos(2x), then what is x?
വൃത്തത്തിന്റെ കേന്ദ്രം ഒരു ________ ആണ്.
If △ ABC is similar to ADEF such that 2AB = DE and BC = 8 cm, then EF is equal to: