If x=2, y=-2 then $X^x+Y^y=$

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x=2, y= -2 ആയാൽ $X^x+Y^y=$

C1 1/8

D $4\frac14$

Answer:

4\frac14

$X=2,Y=-2$

$X^x+Y^y$

$=2^2+(-2)^{-2}$

$=4+\frac{1}{-2^2}$

$=4+\frac14$

$=4\frac14$

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