If xy = 16 and x2+y2=32x^2+y^2=32x2+y2=32then the value of x+y=? A10B4C8D6Answer: C. 8 Read Explanation: (x+y)2=x2+y2+2xy(x+y)^2=x^2+y^2+2xy(x+y)2=x2+y2+2xy(x+y)2=32+2×16(x+y)^2=32+2\times16(x+y)2=32+2×16=32+32=64=32+32=64=32+32=64(x+y)=64=8(x+y)=\sqrt{64}=8(x+y)=64=8 Read more in App
