i+j+k , 2i-2j+2k എന്നീ സാധിശങ്ങൾക്കിടയിലെ കോണളവ് ?Acos−1(2/3){cos}^{-1}(2/3)cos−1(2/3)Bcos−1(1/6){cos}^{-1}(1/6)cos−1(1/6)Ccos−1(5/6){cos}^{-1}(5/6)cos−1(5/6)Dcos−1(1/3){cos}^{-1}(1/3)cos−1(1/3)Answer: cos−1(1/3){cos}^{-1}(1/3)cos−1(1/3) Read Explanation: cosθ=a→.b→∣a→∣∣b→∣cos\theta= \frac{\overset{\rightarrow}{a}.\overset{\rightarrow}{b}}{|\overset{\rightarrow}{a}||\overset{\rightarrow}{b}|}cosθ=∣a→∣∣b→∣a→.b→=2−2+23×23=13=\frac{2-2+2}{\sqrt{3} \times2\sqrt{3}}=\frac{1}{3}=3×232−2+2=31θ=cos−1(1/3)\theta=cos^{-1}(1/3)θ=cos−1(1/3) Read more in App