Question

In ΔPQR, ∠PQR = 90°, PQ = 5 cm and QR = 12. What is the radius (in cm) of the circum circle of ΔPQR?

• A. 6.5
• B. 7.5
• C. 13
• D. 15

Answer 1

Answer:

A. 6.5

 

PR = √(PQ² + QR²)

PR = √(25 + 144) = 13 cm

Radius of circumcircle = hypotenuse/2 = 13/2 = 6.5 cm