In any triangle ABC, cos(A+B/2) is equal to:

Challenger App

★

1M+ Downloads

In any triangle ABC cos- A+B/ 2 is equal to:

ASin C/2

BCos C/2

Csin A/2

Dcos B/2

Answer:

Related Questions:

If 3 sec² x - 4 = 0, then the value of x (0 < x < 90°)

Cos1^o.cos2^o.cos3^o.......................cos100^o is equal to

If tanθ + cotθ = 2 and θ is acute, then the value of tan¹⁰⁰θ +cot¹⁰⁰θ is equal to: