In the figure, AB=4 centimetres, BC =5 centimetres.

Challenger App

★

1M+ Downloads

In the figure, AB=4 centimetres, BC =5 centimetres. <B=90° cos C is:

A5 /√41

B5/4

C4/√41

D4/5

Answer:

Cos C $=\frac{5}{\sqrt{41}}$

Related Questions:

If $sinx=\frac{12}{37}$ , then what is the value of tan x?

Find the value of $\sqrt{cot^2\theta-cos^2\theta}$ .

Find the value of

$Sin0^o\times{sin1^o}\times{sin2^o}\times{sin3^0}...............Sin89^0 is$