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Keshav invests a sum of ₹5400 and Tushar invests a sum of ₹10200 at the same rate of simple interest per annum. If, at the end of 3 years, Tushar gets ₹360 more interest than Keshav, then find the rate of interest per annum (in percentage).

A1.5

B3.5

C2.5

D4.5

Answer:

C. 2.5

Read Explanation:

Use the simple interest formula:

SI=P×R×T100SI = \frac{P \times R \times T}{100}

Let the rate be (R%).

Difference in interest after 3 years is ₹360:

10200×R×31005400×R×3100=360\frac{10200 \times R \times 3}{100} - \frac{5400 \times R \times 3}{100} = 360

(102005400)×R×3100=360\frac{(10200 - 5400)\times R \times 3}{100} = 360

4800×3×R100=360\frac{4800 \times 3 \times R}{100} = 360

144R=360144R = 360

R=360144=2.5R = \frac{360}{144} = 2.5


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  4. a³+b³=(a+b)³ +3ab(a+b)