Keshav invests a sum of ₹5400 and Tushar invests a sum of ₹10200 at the same rate of simple interest per annum. If, at the end of 3 years, Tushar gets ₹360 more interest than Keshav, then find the rate of interest per annum (in percentage).A1.5B3.5C2.5D4.5Answer: C. 2.5 Read Explanation: Use the simple interest formula:SI=P×R×T100SI = \frac{P \times R \times T}{100}SI=100P×R×TLet the rate be (R%).Difference in interest after 3 years is ₹360:10200×R×3100−5400×R×3100=360\frac{10200 \times R \times 3}{100} - \frac{5400 \times R \times 3}{100} = 36010010200×R×3−1005400×R×3=360(10200−5400)×R×3100=360\frac{(10200 - 5400)\times R \times 3}{100} = 360100(10200−5400)×R×3=3604800×3×R100=360\frac{4800 \times 3 \times R}{100} = 3601004800×3×R=360144R=360144R = 360144R=360R=360144=2.5R = \frac{360}{144} = 2.5R=144360=2.5 Read more in App