Let x = √3 + √5 and y = √8 + √2. Which is greater?Ax=yBx>yCx<yDcannot be determinedAnswer: C. x<y Read Explanation: Compare the two values:x=3+5x=\sqrt{3}+\sqrt{5}x=3+5y=8+2y=\sqrt{8}+\sqrt{2}y=8+2Since (8=22)(\sqrt{8}=2\sqrt{2})(8=22),y=22+2=32y=2\sqrt{2}+\sqrt{2}=3\sqrt{2}y=22+2=32Approximate values:(3≈1.732)(\sqrt{3} \approx 1.732)(3≈1.732)(5≈2.236)(\sqrt{5} \approx 2.236)(5≈2.236)So,x≈1.732+2.236=3.968x \approx 1.732+2.236=3.968x≈1.732+2.236=3.968And,y≈3×1.414=4.242y \approx 3\times1.414=4.242y≈3×1.414=4.242Therefore,y>xSo, y is greater. Read more in App