Line through the points (-2,6) and (4,8) is perpendicular to the line through the points (8,12) and (x,24). Find the value of x.A-4B4C3D-3Answer: B. 4 Read Explanation: Slope of the line passing through the points (-2,6) and (4,8)m1=8−64+2=26=13m_1=\frac{8-6}{4+2}=\frac{2}{6}=\frac{1}{3}m1=4+28−6=62=31Slope of the line passing through the points (8,12) and (x,24)m2=24−12x−8=12x−8m_2=\frac{24-12}{x-8}=\frac{12}{x-8}m2=x−824−12=x−812m1×m2=−1m_1 \times m_2=-1m1×m2=−113×12x−8=−1\frac{1}{3}\times\frac{12}{x-8}=-131×x−812=−112=−3x+2412=-3x+2412=−3x+243x=123x=123x=12x=4x=4x=4 Read more in App