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Line through the points (-2,6) and (4,8) is perpendicular to the line through the points (8,12) and (x,24). Find the value of x.

A-4

B4

C3

D-3

Answer:

B. 4

Read Explanation:

Slope of the line passing through the points (-2,6) and (4,8)

m1=864+2=26=13m_1=\frac{8-6}{4+2}=\frac{2}{6}=\frac{1}{3}

Slope of the line passing through the points (8,12) and (x,24)

m2=2412x8=12x8m_2=\frac{24-12}{x-8}=\frac{12}{x-8}

m1×m2=1m_1 \times m_2=-1

13×12x8=1\frac{1}{3}\times\frac{12}{x-8}=-1

12=3x+2412=-3x+24

3x=123x=12

x=4x=4


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