ATuesday
BSaturday
CSunday
DThursday
Answer:
B. Saturday
Read Explanation:
Solution:
No. of Odd days | Ordinary Year | Leap Year |
365 ÷ 7 = 52 weeks + 1 odd day | 366 ÷ 7 = 52 weeks + 2 odd day |
Years | No. of odd days |
100 years | 5 |
200 years | 3 |
300 years | 1 |
400 years | 0 |
Note: Multiple of 400 years i.e. 800, 1200, 1600, 2000 have 0 odd days.
Calculating leap year: For Finding the number of leap year (1 - 99) years, divide the number of years by 4 and the quotient will be the number of leap years.
Code for weekdays:
No. of odd days | Day |
0 | Sunday |
1 | Monday |
2 | Tuesday |
3 | Wednesday |
4 | Thursday |
5 | Friday |
6 | Saturday |
1987 = we find out the odd days (the nearest leap century year + the nearest century year + completing year) = 1900 + 86 year + year 1987
In 1900 year the odd days = 1 odd day
In 86 years, odd days = 21 leap year + 65 ordinary years
21 Leap year = 42 Year = 0 odd day
65 Normal Year = 65 Year = 2 odd day
Odd days in 1 January to 1 August:
In 1987, the number of days up to 1 August = 31 (Jan) + 28 (Feb - normal year) + 31(Mar) + 30(Apr) + 31(May) + 30 (June) + 31(July) + 1 (Aug) = 213 / 7 = 3 odd days.
Total = 1 + 0 + 2 + 3 = 6 days
6 is the code for Saturday.
Hence, 1st August, 1987 is Saturday.