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a,b\overset{\rightarrow}{a}, \overset{\rightarrow}{b} എന്നിവ രണ്ടു സദിശങ്ങളാണ്a=2,b=3,a.b=4|\overset{\rightarrow}{a}|=2, |\overset{\rightarrow}{b}|=3, \overset{\rightarrow}{a}.\overset{\rightarrow}{b}=4 ആയാൽ ab|\overset{\rightarrow}{a}-\overset{\rightarrow}{b}|കണ്ടുപിടിക്കുക .

A√6

B√3

C√5

D2

Answer:

C. √5

Read Explanation:

ab2=(ab).(ab){|\overset{\rightarrow}{a}-\overset{\rightarrow}{b}|}^2=(\overset{\rightarrow}{a}-\overset{\rightarrow}{b}).(\overset{\rightarrow}{a}-\overset{\rightarrow}{b})

=a.aa.bb.a+b.b=\overset{\rightarrow}{a}.\overset{\rightarrow}{a}-\overset{\rightarrow}{a}.\overset{\rightarrow}{b}-\overset{\rightarrow}{b}.\overset{\rightarrow}{a}+\overset{\rightarrow}{b}.\overset{\rightarrow}{b}

=a22(a.b)+b2=\overset{\rightarrow}{|a^2|}-2(\overset{\rightarrow}{a}.\overset{\rightarrow}{b})+\overset{\rightarrow}{|b^2|}

=222×4+32=2^2-2\times4+3^2

=48+9=4-8+9

=5=5

ab=5|\overset{\rightarrow}{a}-\overset{\rightarrow}{b}|=\sqrt5


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