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(323+2)+(3+232)= (\frac {\sqrt{3}-\sqrt{2}}{\sqrt{3}+\sqrt{2}})+(\frac {\sqrt{3}+\sqrt{2}}{\sqrt{3}-\sqrt{2}}) =

A5

B$2\sqrt{2}$

C$3\sqrt{2}$

D10

Answer:

D. 10

Read Explanation:

(323+2)+(3+232)= (\frac {\sqrt{3}-\sqrt{2}}{\sqrt{3}+\sqrt{2}})+(\frac {\sqrt{3}+\sqrt{2}}{\sqrt{3}-\sqrt{2}}) =

$$ഛേദത്തിന്റെ LCM കണ്ടുപിടിച്ചു അംശത്തെയും ഛേദത്തെയും LCM കൊണ്ട് ഗുണിച്ചാൽ

$\frac{(\sqrt{3}-\sqrt{2})^2+(\sqrt{3}+\sqrt{2})^2}{(\sqrt{3}+\sqrt{2})(\sqrt{3}-\sqrt{2})} = $

$\frac{3-2\sqrt{6}+2+3+2\sqrt{6}+2}{\sqrt{3}^2 - \sqrt{2}^2} =$

$\frac{10}{3-2}=10$


Related Questions:

A positive number exceed its positive square root by 30. Find the number.
Find two consecutive natural numbers whose squares have been the sum 221.

30+31+22+x \sqrt {{30 }+ \sqrt {31}+ \sqrt{22+x}}

$$find x

27+27+27+..........=?\sqrt{27+\sqrt{27+\sqrt{27+..........}}}=?

421+621=?4\sqrt{21}+6\sqrt{21}=?