App Logo

No.1 PSC Learning App

1M+ Downloads

999212=999^2-1^2=

A181880

B998000

C989880

D1818000

Answer:

B. 998000

Read Explanation:

999212=(999+1)(9991)999^2-1^2=(999+1)(999-1)

=1000×998=998000=1000\times998=998000


Related Questions:

Find two consecutive natural numbers whose squares have been the sum 221.
980 -നെ ഏറ്റവും ചെറിയ ഏതു സംഖ്യകൊണ്ട് ഗുണിച്ചാൽ അതൊരു പൂർണവർഗമാകും

0.01+0.81+1.21+0.0009=?\sqrt{0.01}+\sqrt{0.81}+\sqrt{1.21}+\sqrt{0.0009}=?

(1+1/x)(1+1x+1)(1+1x+2)(1+1x+3)=?(1+1/x)(1+\frac1{{x+1}})(1+\frac1{x+2})(1+\frac1{x+3})=?

The value of 324+0.01696.76\sqrt{324}+\sqrt{0.0169}-\sqrt{6.76}