(23+12)÷(23−12)÷7=?(\frac23+\frac12)\div(\frac23-\frac12)\div7=?(32+21)÷(32−21)÷7=? A7/42B1/42C1/7D1Answer: D. 1 Read Explanation: (23+12)÷(23−12)÷7(\frac23+\frac12)\div(\frac23-\frac12)\div7(32+21)÷(32−21)÷7 =4+36÷4−36÷7=\frac{4+3}{6}\div\frac{4-3}{6}\div7=64+3÷64−3÷7 =76×61×17=1=\frac76\times\frac61\times\frac17=1=67×16×71=1 Read more in App