36+3x23+28÷162=13×4\frac{36+3x}{23}+2^8\div16^2=13\times42336+3x+28÷162=13×4ആയാൽ x എത്ര? A379B360C367D350Answer: A. 379 Read Explanation: 36+3x23+28÷162=13×4\frac{36+3x}{23}+2^8\div16^2=13\times42336+3x+28÷162=13×4 36+3x23+28÷28=13×4\frac{36+3x}{23}+2^8\div2^8=13\times42336+3x+28÷28=13×4 3x=52×23+23−36 ⟹ 3x=1137 ⟹ x=3793x=52\times23+23-36\implies3x=1137\implies{x}=3793x=52×23+23−36⟹3x=1137⟹x=379 Read more in App
