Question

$\frac{36+3x}{23}+2^8\div16^2=13\times4$ആയാൽ x എത്ര?

• A. 379
• B. 360
• C. 367
• D. 350

Answer 1

Answer:

A. 379

$\frac{36+3x}{23}+2^8\div16^2=13\times4$

$\frac{36+3x}{23}+2^8\div2^8=13\times4$

$3x=52\times23+23-36\implies3x=1137\implies{x}=379$