$3^{10}×27^{2}=9^{2}×3^{n}$What is the value of n?

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$3^{10}×27^{2}=9^{2}×3^{n}$

n ന്റെ വിലയെന്ത്?

C12

Answer:

3^10×27^2=9^2×3^n 3^10×(3^3^)2=(3^2)^2×3^n 3^10×3^6=3^4×3^n 3^16=3^4+n 4 + n = 16 n = 16 - 4 = 12

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