Sanu's present age is one fourth of his father's age. Father has 30 years more than Sanu. The
present age of Sanu :
A12
B20
C10
D15
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+ = ÷, ÷ = - , - = ×,× = + എന്നിങ്ങനെയായാൽ
48 + 16 ÷ 4 - 2 × 8 =
The general solution of second order equation x 2 y" + 3xy' + y = 0) is
"L" in Roman letters means
2.22+222+2.2-0.002= എത്ര?
B is twice as old as A but twice younger than F. C is half the age of A but twice older than D.Which two persons from the pair of the oldest and the youngest ?