Question

Seven people R, S, T, D, E, F and G are sitting around a circular table, facing the centre (but not necessarily in the same order). T is sitting to the immediate right of G. R is sitting to the immediate right of E. Only two people are sitting between D and S when counted from the right of S. E is an immediate neighbour of S. If F is not an immediate neighbour of S, who is sitting third to the left of F?

• A. R
• B. T
• C. E
• D. S

Answer 1

Answer:

C. E

(All are facing the centre → Right = anticlockwise, Left = clockwise)

Step 1: Fix S as reference

“Only two people are sitting between D and S when counted from the right of S”

So moving anticlockwise from S:
$S ; \rightarrow ; <em>; \rightarrow ; </em>; \rightarrow ; D$

Step 2: Use the neighbour condition

“E is an immediate neighbour of S”

If E were to the left of S, then:

“R is sitting to the immediate right of E”
would force R = S, which is impossible.

Therefore, E is to the immediate right of S.

So anticlockwise from S:
$S \rightarrow E \rightarrow R \rightarrow D$

Step 3: Place remaining people

People left: T, G, F

“F is not an immediate neighbour of S”
So F cannot sit next to S.

“T is sitting to the immediate right of G”
(T is anticlockwise to G)

A valid arrangement (clockwise) is:
$S ;-; T ;-; G ;-; F ;-; D ;-; R ;-; E$

(All conditions are satisfied ✔️)

Who is sitting third to the left of F?

Left = clockwise

From F:

• 1st left → D

• 2nd left → R

• 3rd left → E