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Sharad invested two equal amounts for 6 years and 3 years at the rate of 7% and 9% per annum, respectively. The sum of their simple interest is ₹1,587. The invested amount (in ₹) by Sharad is:

A4650

B4600

C4374

D4550

Answer:

B. 4600

Read Explanation:

Let each investment = ₹(x)

Simple interest for both

For 6 years at 7%:
SI1=x×7×6100=0.42xSI_1 = \frac{x \times 7 \times 6}{100} = 0.42x

For 3 years at 9%:
SI2=x×9×3100=0.27xSI_2 = \frac{x \times 9 \times 3}{100} = 0.27x

Total interest

0.42x+0.27x=0.69x0.42x + 0.27x = 0.69x

Given:
0.69x=15870.69x = 1587

Solve

x=15870.69=2300x = \frac{1587}{0.69} = 2300

Total invested amount

Since two equal amounts:
2x=2×2300=46002x = 2 \times 2300 = 4600


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