Question

Simplify

• A. -1
• B. 0
• C. 1
• D. 2

Answer 1

Answer:

B. 0

$[\frac{1}{{243}^{-1/5}}-\frac{1}{32^{-1/5}}]^{-1}+[\frac{1}{{3^{-1}}}-\frac{1}{4^{-1}}]^{-1}$

$\frac{1}{{243}^{-1/5}} =( \frac{1}{3^5})^{-1/5} = (3^5)^{\frac{1}{5}}=3$

$\frac{1}{32^{-1/5}} = \frac{1}{(2^5)^{-1/5}} = (2^5)^{\frac{1}{5}} = 2$

$\frac{1}{{3^{-1}}} = 3$

$\frac{1}{4^{-1}} = 4$

= $(3-2)^{-1} + (3 - 4)^{-1}$

= $1^{-1} + (-1)^{-1}$

= $\frac{1}{1} + \frac{1}{-1}$

= 1 - 1 = 0