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Simplify:
[(23)+(45÷27)]÷[(32)(56×34)][(\frac{2}{3})+(\frac{4}{5}\div\frac{2}{7})]\div [(\frac{3}{2})-(\frac{5}{6}\times\frac{3}{4})]

A416/105

B418/110

C425/250

D526/350

Answer:

A. 416/105

Read Explanation:

Simplify:

[
\left[\frac{2}{3}+\left(\frac{4}{5}\div\frac{2}{7}\right)\right]\div\left[\frac{3}{2}-\left(\frac{5}{6}\times\frac{3}{4}\right)\right]
]

Step 1: Simplify the first bracket

[
\frac{4}{5}\div\frac{2}{7}
= \frac{4}{5}\times\frac{7}{2}
= \frac{28}{10}
= \frac{14}{5}
]

Now,

23+145\frac{2}{3}+\frac{14}{5}
=1015+4215= \frac{10}{15}+\frac{42}{15}
=5215= \frac{52}{15}

Simplify the second bracket

56×34\frac{5}{6}\times\frac{3}{4}
=1524= \frac{15}{24}
=58= \frac{5}{8}

Now,

3258\frac{3}{2}-\frac{5}{8}
=12858= \frac{12}{8}-\frac{5}{8}
=78= \frac{7}{8}

Divide the two results

5215÷78\frac{52}{15}\div\frac{7}{8}
=5215×87= \frac{52}{15}\times\frac{8}{7}
=416105= \frac{416}{105}

Since 416 and 105 have no common factor, the fraction is already in simplest form.

Answer:

416105\boxed{\frac{416}{105}}


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