Question

Simplify:

$(\frac{1-1}{10})(\frac{1-1}{11})(\frac{1-1}{12})-(\frac{1-1}{99})(\frac{1-1}{100})=?$

• A. $$\frac{9}{100}$$
• B. $$\frac{999}{10000}$$
• C. $$\frac{1}{10000}$$
• D. 0

Answer 1

Answer:

D. 0

$(\frac{1-1}{10})(\frac{1-1}{11})(\frac{1-1}{12})-(\frac{1-1}{99})(\frac{1-1}{100})=?$

$⇒(\frac{0}{100})(\frac{0}{11})(\frac{0}{12})-(\frac{0}{99})(\frac{0}{100})=?$

⇒ 0 – 0 = ?

⇒ 0 = ?

Note: This is an exam question in which error was found we have given the solution according to the question.