Question

$\sqrt {{30 }+ \sqrt {31+ \sqrt{22+x}}}=6$

$\text{find x}$

• A. 5
• B. 3
• C. 7
• D. 6

Answer 1

Answer:

B. 3

$\sqrt {{30 }+ \sqrt {31+ \sqrt{22+x}}}$

the perfect square after 22 is 25, So x = 25 - 22 =3

$\sqrt {{30 }+ \sqrt {31+ \sqrt{22+x}}}$

$= \sqrt {{30 }+ \sqrt {31+ \sqrt{22+3}}}$

$=\sqrt {{30 }+ \sqrt {31+ \sqrt{25}}}$

$=\sqrt {{30 }+ \sqrt {31+ 5}}$

$= \sqrt {{30 }+ \sqrt {36}}$

$=\sqrt {{30 }+ 6}$

$=\sqrt {36}$

$=6$