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2025+30310+x=(22)2\sqrt{20\frac25+30\frac{3}{10}+x}=(2\sqrt{2})^2

$$ആയാൽ x ൻ്റെ വില എത്ര?

A1010310\frac{10}{3}

B1331013\frac{3}{10}

C310133\frac{10}{13}

Dഇവയൊന്നും അല്ല

Answer:

1331013\frac{3}{10}

Read Explanation:

2025+30310+x=(22)2\sqrt{20\frac25+30\frac{3}{10}+x}=(2\sqrt{2})^2

2025+30310+x=8\sqrt{20\frac25+30\frac{3}{10}+x}=8

2025+30310+x=82=6420\frac25+30\frac{3}{10}+x= 8^2=64

20+30+2/5+3/10+x=6420+30+2/5+3/10+x=64

50+7/10+x=6450+7/10+x=64

x=64507/10x=64-50-7/10

x=147/10x=14-7/10

x=(1407)/10x=(140-7)/10

x=133/10x=133/10

x=13310x=13\frac{3}{10}


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