ab3a4b46=\sqrt[3]{ab} \sqrt[6]{a^4b^4} =\rule{ 1cm}{ 0.1pt }3ab6a4b4= A$ab$B$\sqrt[3]{a^5b^5}$C$\sqrt[6]{a^5b^5}$D$\sqrt[9]{a^5b^5}$Answer: $ab$ Read Explanation: ആദ്യ പദം: ab3=(ab)13\sqrt[3]{ab} = (ab)^{\frac{1}{3}}3ab=(ab)31രണ്ടാം പദം: a4b46=(a4b4)16=(ab)46=(ab)23\sqrt[6]{a^4b^4} = (a^4b^4)^{\frac{1}{6}} = (ab)^{\frac{4}{6}} = (ab)^{\frac{2}{3}}6a4b4=(a4b4)61=(ab)64=(ab)32ഇവ തമ്മിൽ ഗുണിക്കുമ്പോൾ കൃതികൾ (powers) തമ്മിൽ കൂട്ടണം:(ab)13×(ab)23=(ab)13+23=(ab)33=(ab)1=ab(ab)^{\frac{1}{3}} \times (ab)^{\frac{2}{3}} = (ab)^{\frac{1}{3} + \frac{2}{3}} = (ab)^{\frac{3}{3}} = (ab)^1 = \mathbf{ab}(ab)31×(ab)32=(ab)31+32=(ab)33=(ab)1=ab Read more in App