App Logo

No.1 PSC Learning App

1M+ Downloads

Find the area of the parallelogram with sides AB = 6, AC = 3, ∠ BAC = 60

1000114769.jpg

A12

B9√3

C18

D9

Answer:

B. 9√3

Read Explanation:

Area = ab × sinx

= 6 × 3 × sin60

= 6 × 3 ×3/2

= 93


Related Questions:

Find the distance between top and bottom side of the parallelogram ABCD with side AC = 8, angle BAC = 60°

1000114769.jpg

The value of cosec230sin245+sec260tan60cosec245sec260tan45\frac{{\rm cose{c^2}30^\circ {{\rm \sin }^2}45^\circ + {{\rm \sec }^2}60^\circ }}{{\rm tan60^\circ \rm cose{c^2}45^\circ - {{\rm \sec }^2}60^\circ \rm tan45^\circ }}  is:

The value of sin (60 + θ) - cos (30 - θ) is
If tan 45o + sec 60o = x, fine the value of x.
Two angles are complementary. The larger angle is 6º less than thrice the measure of the smaller angle. What is the measure of the larger angle?