If x2+1/x2=38 x^2+1/x^2=38x2+1/x2=38 findx−1/xx-1/xx−1/x A10B8C6D4Answer: C. 6 Read Explanation: (x−1/x)2=x2+2−1/x2(x-1/x)^2=x^2+2-1/x^2(x−1/x)2=x2+2−1/x2(x−1/x)2=x2+1/x2−2=38−2=36(x-1/x)^2=x^2+1/x^2-2=38-2=36(x−1/x)2=x2+1/x2−2=38−2=36 x−1/x=36=6x-1/x=\sqrt{36}=6x−1/x=36=6 Read more in App
