If 4x - 3y = 12 and xy = 5 , then find the value of$\frac{16x^2+9y^2}{8}$

Challenger App

★

1M+ Downloads

If 4x - 3y = 12 and xy = 5 , then find the value of $\frac{16x^2+9y^2}{8}$

A33

B15

C18

D44

Answer:

4x - 3y = 12

$(4x-3y)^2=12^2$

$16x^2+9y^2-24xy=144$

$16x^2+9y^2-24\times5 = 144$

$16x^2+9y^2=144+120=264$

$\frac{16x^2+9y^2}{8}=264/8$

$=33$

Related Questions:

If S = 3T/2, then express 'T' as a percentage of S + T.

If, $(x+\frac{1}{x})=4$ , then the value of $x^4+\frac{1}{x^4}$ is:

If x : y = 2 : 3 then the value of $\frac{3x+2y}{9x+5y}$ will be