If a + b =10 and 3/7 of ab = 9,then the value of a3+b3=?a^3+b^3=?a3+b3=? A270B370C200D142Answer: B. 370 Read Explanation: a3+b3=(a+b)(a2−ab+b2)a^3+b^3=(a+b)(a^2-ab+b^2)a3+b3=(a+b)(a2−ab+b2)3/7×ab=93/7\times{ab}=93/7×ab=9 ⟹ ab=9×7/3=21\implies{ab}={9\times7}/3=21⟹ab=9×7/3=21(a+b)2=a2+2ab+b2(a+b)^2=a^2+2ab+b^2(a+b)2=a2+2ab+b2102=a2+b2+2×2110^2=a^2+b^2+2\times21102=a2+b2+2×21a2+b2=100−42=58a^2+b^2=100-42=58a2+b2=100−42=58a3+b3=(10)(58−21)a^3+b^3=(10)(58-21)a3+b3=(10)(58−21)=370=370=370 Read more in App