If (a+1/a−3)2=49(a+1/a-3)^2=49(a+1/a−3)2=49then find a2+1/a2a^2+1/a^2a2+1/a2 A100B99C98D97Answer: C. 98 Read Explanation: (a+1/a−3)2=49(a+1/a-3)^2=49(a+1/a−3)2=49a+1/a−3=49=7a+1/a-3=\sqrt{49}=7a+1/a−3=49=7 a+1/a−3=7a+1/a-3=7a+1/a−3=7 a+1/a=7+3=10a+1/a=7+3=10a+1/a=7+3=10 a2+1/a2=102−2a^2+1/a^2=10^2-2a2+1/a2=102−2 =100−2=98=100-2=98=100−2=98 if a+1/a=ka+1/a=ka+1/a=k then a2+1/a2=k2−2a^2+1/a^2=k^2-2a2+1/a2=k2−2 Read more in App