If (a+1/a−3)2=16(a+1/a-3)^2=16(a+1/a−3)2=16 then find a2+1/a2a^2+1/a^2a2+1/a2 A47B49C7D3Answer: A. 47 Read Explanation: (a+1/a−3)2=16(a+1/a-3)^2=16(a+1/a−3)2=16a+1/a−3=16=4a+1/a-3=\sqrt{16}=4a+1/a−3=16=4a+1/a−3=4a+1/a-3=4a+1/a−3=4a+1/a=4+3=7a+1/a=4+3=7a+1/a=4+3=7a2+1/a2=72−2a^2+1/a^2=7^2-2a2+1/a2=72−2=49−2=47=49-2=47=49−2=47if a+1/a=ka+1/a=ka+1/a=k then a2+1/a2=k2−2a^2+1/a^2=k^2-2a2+1/a2=k2−2 Read more in App