If $(2^x)(2^y)=8$ and $(9^x)(3^y)=81$, what are the values of x, y?

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$(2^x)(2^y)=8 , (9^x)(3^y)=81$ So what is the value of x and y?

A1,2

B2,1

C1,1

D2,2

Answer:

$(2^x)(2^y)=2^{x+y}=8=2^3\implies{x+y}=3....(1)$

$9^x\times3^y=3^{2x+y}=81=3^4\implies{2x+y}=4....(2)$

$(2)-(1)\implies{x}=1,y=2$

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