Ifx2+1/x2=38x^2+1/x^2=38x2+1/x2=38then what is the value of |x-1/x|? A5B6C12D18Answer: B. 6 Read Explanation: If x2+1/x2=kx^2+1/x^2=kx2+1/x2=kthen, x−1/x=k−2x-1/x=\sqrt{k-2}x−1/x=k−2So here,x2+1/x2=38x^2+1/x^2=38x2+1/x2=38 then, x−1/x=38−2=36=6x-1/x=\sqrt{38-2}=\sqrt{36}=6x−1/x=38−2=36=6 Read more in App