Let fand g be the functions from R to R such thatf(x)=2x and g(x)=x2 What is fg ?
A2x3
B2x2
C4x5
D8x3
Answer:
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Understanding Function Operations
Functions can be combined using various algebraic operations to form new functions.
For two functions f and g mapping from a set R to R (real numbers to real numbers), common operations include addition (f+g), subtraction (f-g), multiplication (fg or f*g), division (f/g), and composition (f o g).
Function Multiplication (fg)
When the notation fg is used, it specifically represents the product of the functions f(x) and g(x).
Mathematically, the product function is defined as (fg)(x) = f(x) * g(x). This means you multiply the output values of f and g for a given input x.
Step-by-Step Calculation
Given the function f(x) = 2x.
Given the function g(x) = x^2.
To find (fg)(x), we substitute the expressions for f(x) and g(x) into the definition of function multiplication: (fg)(x) = (2x) * (x^2).
Applying the rules of exponents (specifically, a^m * a^n = a^(m+n)), where x can be considered x^1: x * x^2 = x^(1+2) = x^3.
Therefore, (fg)(x) = 2 * x^3 = 2x^3.
Distinction: Function Multiplication vs. Function Composition
It is crucial for competitive exams to understand the difference between function multiplication (fg(x) = f(x) * g(x)) and function composition ((f o g)(x) = f(g(x))).
For example, with the given functions:
Function Multiplication: (fg)(x) = 2x * x^2 = 2x^3.
Function Composition: (f o g)(x) = f(g(x)) = f(x^2) = 2(x^2) = 2x^2.
Another composition: (g o f)(x) = g(f(x)) = g(2x) = (2x)^2 = 4x^2.
These operations yield different results and notations, so accurate interpretation is vital.
Domain of Combined Functions
For algebraic operations like multiplication, the domain of the resulting function (fg) is the intersection of the domains of the individual functions (f and g).
Since both f(x) = 2x and g(x) = x^2 are defined for all real numbers (Domain = R), their product fg(x) = 2x^3 is also defined for all real numbers.
Domain of f is R.
Domain of g is R.
Domain of fg is R ∩ R = R.