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(3+3)(33)=(3+\sqrt3)(3-\sqrt3)=

A6

B9

C0

D3

Answer:

A. 6

Read Explanation:

(a+b)(ab)=a2b2\because(a+b)(a-b)=a^2-b^2

(3+3)(33)(3+\sqrt3)(3-\sqrt3)

=32(3)2=3^2-(\sqrt3)^2

=93=9-3

=6=6


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