A=1−1n;n∈NA={1-\frac{1}{n};n∈N}A=1−n1;n∈N എന്ന ഗണത്തിൽ Inf(A), Sup(A) ഏത്? A0&1/2B0&2C0&1D1/2&2Answer: C. 0&1 Read Explanation: Sup A = 1Inf A = 0 Read more in App