Find the value of Sec (-30o)+tan(-60o)

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Find the value of Sec (-30^o)+tan(-60^o)

B-2

D-1

Answer:

Sec (-30^o) x tan(-60^o)

Sec(-θ)=Secθ

tan(-θ)=-tanθ

Sec (-30^o) x tan(-60^o)=Sec30^ox(-tan60^o)

$=\frac{2}{\sqrt{3}}\times{-\sqrt{3}}$

$=-2$

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