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In the given figure, if PQ = 13 cm and PR = 12 cm then the value of sin θ + tan θ = ?

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A218/5

B213/5

C216/13

D216/65

Answer:

D. 216/65

Read Explanation:

Solution:

Given:

PQ = 13 cm and PR = 12 cm

Concept used:

(Perpendicular)2 + (Base)2 = (Hypotaneous)2

sin θ = p/h and tan θ = p/b 

Calculation:

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QR2 = 132 - 122 = 25

⇒ QR = 5 cm

now,

sin θ + tan θ = (p/h) + (p/b)

⇒ (12/13) + (12/5) = (60 + 156)/65

⇒ 216/65 

∴ The value of sin θ + tan θ is 216/65.


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