App Logo

No.1 PSC Learning App

1M+ Downloads

In the given figure, ∠BAC = 70°, ∠EBC = 140°, then ∠ACD is

image.png

A120°

B100°

C110°

D105°

Answer:

C. 110°

Read Explanation:

Solution: Given: ∠EBC = 140∘ and ∠BAC = 70∘ Concept: Exterior angle: The angle formed between one side of a triangle and the extension of its adjacent side is called the exterior angle.​ Theorem: The exterior angle so formed is equal to the sum of the two interior opposite angles. This is called the exterior angle theorem of the triangle. In the above diagram, ∠A and ∠B represent the interior angle but ∠ACD represents the exterior angle. so according to the exterior angle theorem, ∠ACD = ∠​A + ∠B Calculation: ∵ ∠EBC + ∠ABC = 180∘ ⇒ 140∘ + ∠ABC = 180∘ ⇒ ∠ABC = 180∘ - 140∘ ⇒ ∠ABC = 40∘ .........(1) ∵ ∠ACD = ∠BAC + ∠ABC ∴ ∠ACD = 70∘ + 40∘ (From 1st) ⇒ ∠ACD = 110∘


Related Questions:

In a GP 3rd term is 24 and 6th term is 192. Find the tenth term:
Find a, so that a, a + 2, a+ 6 are consecutive terms of a GP:
What is the sum of infinite geometric series with first term equal to 1 and common ratio is ½?
ഒരു സമഗുണിത പ്രോഗ്രഷനിലെ ഏഴാം പദം 320, ഒന്നാംപദം 5 ആയാൽ പൊതുഗുണകം എത്ര ?
If the nth term of a GP is 128 and both the first term a and the common ratio r are 2. Find the number of terms in the GP.