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The area of a rhombus is 240 cm2 and one diagonal is 16 cm. Find the second diagonal.

A16 cm

B20 cm

C30 cm

D36 cm

Answer:

C. 30 cm

Read Explanation:

Solution:

Given:

Area of rhombus = 240 cm2

One diagonal = 16 cm

Concept used:

Area of Rhombus = 1/2 × d1 × d2 

Where d1, d2 are the diagonal of the rhombus.

Calculation:

According to the question,

⇒ 1/2 × 16 × d2 = 240 

⇒ d2 = (240 × 2)/16 

⇒ d2 = 480/16 = 30 cm

∴ The second diagonal is 30cm.


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ഒരു സമപാർശ്വ ത്രികോണത്തിന്റെ തുല്യമല്ലാത്തവശം 4/3- സെ.മീ. ആണ്. ഇതിന്റെ ചുറ്റളവ്4(2/15) സെ.മീ. ആയാൽ തുല്യമായ വശത്തിന്റെ നീളം എത്ര ?.